二次剩余定理Unknown# What$(p-a)^{2} \equiv a^{2} \pmod{p}$$x^{2} = a \pmod{p}$ has either no solutions or exactly 2 incongruent solutions modulo p; when p and a coprime# Properties$QR \times QR = QR$$QNR \times QR = QNR$$QNR \times QNR = QR$# Links二次剩余 - 维基百科,自由的百科全书